Base | Representation |
---|---|
bin | 11111100011001101… |
… | …00000010111000001 |
3 | 1121201110102001020012 |
4 | 33301212200113001 |
5 | 234142201224321 |
6 | 11440434354305 |
7 | 1136514134204 |
oct | 176146402701 |
9 | 47643361205 |
10 | 16938304961 |
11 | 7202260246 |
12 | 334872b995 |
13 | 179c2a1a76 |
14 | b6981d93b |
15 | 69208c05b |
hex | 3f19a05c1 |
16938304961 has 2 divisors, whose sum is σ = 16938304962. Its totient is φ = 16938304960.
The previous prime is 16938304939. The next prime is 16938304963. The reversal of 16938304961 is 16940383961.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12973210000 + 3965094961 = 113900^2 + 62969^2 .
It is an emirp because it is prime and its reverse (16940383961) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16938304961 - 210 = 16938303937 is a prime.
Together with 16938304963, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (16938304963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8469152480 + 8469152481.
It is an arithmetic number, because the mean of its divisors is an integer number (8469152481).
Almost surely, 216938304961 is an apocalyptic number.
It is an amenable number.
16938304961 is a deficient number, since it is larger than the sum of its proper divisors (1).
16938304961 is an equidigital number, since it uses as much as digits as its factorization.
16938304961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 839808, while the sum is 50.
The spelling of 16938304961 in words is "sixteen billion, nine hundred thirty-eight million, three hundred four thousand, nine hundred sixty-one".
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