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16945251613 = 23399724187
BaseRepresentation
bin11111100100000010…
…00000010100011101
31121201221110222020121
433302001000110131
5234200441022423
611441243314541
71136630155633
oct176201002435
947657428217
1016945251613
117206175384
12334ab1ba51
1317a0864904
14b6a70b353
156929b045d
hex3f204051d

16945251613 has 4 divisors (see below), whose sum is σ = 16945999200. Its totient is φ = 16944504028.

The previous prime is 16945251611. The next prime is 16945251689. The reversal of 16945251613 is 31615254961.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16945251613 - 21 = 16945251611 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 16945251613.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16945251611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 338695 + ... + 385492.

It is an arithmetic number, because the mean of its divisors is an integer number (4236499800).

Almost surely, 216945251613 is an apocalyptic number.

It is an amenable number.

16945251613 is a deficient number, since it is larger than the sum of its proper divisors (747587).

16945251613 is an equidigital number, since it uses as much as digits as its factorization.

16945251613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 747586.

The product of its digits is 194400, while the sum is 43.

The spelling of 16945251613 in words is "sixteen billion, nine hundred forty-five million, two hundred fifty-one thousand, six hundred thirteen".

Divisors: 1 23399 724187 16945251613