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16950849341 is a prime number
BaseRepresentation
bin11111100100101100…
…10110111100111101
31121202100000100212212
433302112112330331
5234203404134331
611442003310205
71140025561556
oct176226267475
947670010785
1016950849341
117209348aa8
12335097b365
1317a1a7478a
14b6b36732d
15693218d2b
hex3f2596f3d

16950849341 has 2 divisors, whose sum is σ = 16950849342. Its totient is φ = 16950849340.

The previous prime is 16950849323. The next prime is 16950849353. The reversal of 16950849341 is 14394805961.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12018736900 + 4932112441 = 109630^2 + 70229^2 .

It is a cyclic number.

It is not a de Polignac number, because 16950849341 - 218 = 16950587197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 16950849341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16950845341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8475424670 + 8475424671.

It is an arithmetic number, because the mean of its divisors is an integer number (8475424671).

Almost surely, 216950849341 is an apocalyptic number.

It is an amenable number.

16950849341 is a deficient number, since it is larger than the sum of its proper divisors (1).

16950849341 is an equidigital number, since it uses as much as digits as its factorization.

16950849341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 933120, while the sum is 50.

The spelling of 16950849341 in words is "sixteen billion, nine hundred fifty million, eight hundred forty-nine thousand, three hundred forty-one".