Base | Representation |
---|---|
bin | 1111011110010011011111… |
… | …1110010110111010010111 |
3 | 2020020110022110001112222222 |
4 | 3313210313332112322113 |
5 | 4212221221431144421 |
6 | 100103445413212555 |
7 | 3404112355424216 |
oct | 367446776267227 |
9 | 66213273045888 |
10 | 17013304553111 |
11 | 546a33597aaa9 |
12 | 1aa936133115b |
13 | 965469c88b89 |
14 | 42b63c32b07d |
15 | 1e784d6a1cab |
hex | f7937f96e97 |
17013304553111 has 4 divisors (see below), whose sum is σ = 17014507516032. Its totient is φ = 17012101590192.
The previous prime is 17013304553087. The next prime is 17013304553153. The reversal of 17013304553111 is 11135540331071.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 17013304553111 - 230 = 17012230811287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (17013304558111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601460246 + ... + 601488531.
It is an arithmetic number, because the mean of its divisors is an integer number (4253626879008).
Almost surely, 217013304553111 is an apocalyptic number.
17013304553111 is a deficient number, since it is larger than the sum of its proper divisors (1202962921).
17013304553111 is a wasteful number, since it uses less digits than its factorization.
17013304553111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1202962920.
The product of its (nonzero) digits is 18900, while the sum is 35.
Adding to 17013304553111 its reverse (11135540331071), we get a palindrome (28148844884182).
The spelling of 17013304553111 in words is "seventeen trillion, thirteen billion, three hundred four million, five hundred fifty-three thousand, one hundred eleven".
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