Search a number
-
+
1703485331983 is a prime number
BaseRepresentation
bin11000110010011111101…
…000110101101000001111
320000211222211012000212201
4120302133220311220033
5210402214221110413
63342323110342331
7234033645261211
oct30623750655017
96024884160781
101703485331983
115a7498073046
1223619195a9a7
13c483a8378a6
145c6405ac5b1
152e4a17ce9dd
hex18c9fa35a0f

1703485331983 has 2 divisors, whose sum is σ = 1703485331984. Its totient is φ = 1703485331982.

The previous prime is 1703485331921. The next prime is 1703485332007. The reversal of 1703485331983 is 3891335843071.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1703485331983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1703485331083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 851742665991 + 851742665992.

It is an arithmetic number, because the mean of its divisors is an integer number (851742665992).

Almost surely, 21703485331983 is an apocalyptic number.

1703485331983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1703485331983 is an equidigital number, since it uses as much as digits as its factorization.

1703485331983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6531840, while the sum is 55.

The spelling of 1703485331983 in words is "one trillion, seven hundred three billion, four hundred eighty-five million, three hundred thirty-one thousand, nine hundred eighty-three".