17045113 has 4 divisors (see below), whose sum is σ = 17065728. Its totient is φ = 17024500.

The previous prime is 17045111. The next prime is 17045117. The reversal of 17045113 is 31154071.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31154071 = 13 ⋅2396467.

It is a cyclic number.

It is not a de Polignac number, because 17045113 - 2¹ = 17045111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (17045111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9013 + ... + 10738.

It is an arithmetic number, because the mean of its divisors is an integer number (4266432).

Almost surely, 2^17045113 is an apocalyptic number.

It is an amenable number.

17045113 is a deficient number, since it is larger than the sum of its proper divisors (20615).

17045113 is an equidigital number, since it uses as much as digits as its factorization.

17045113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20614.

The product of its (nonzero) digits is 420, while the sum is 22.

The square root of 17045113 is about 4128.5727558080. The cubic root of 17045113 is about 257.3554056717.

Adding to 17045113 its reverse (31154071), we get a palindrome (48199184).

The spelling of 17045113 in words is "seventeen million, forty-five thousand, one hundred thirteen".