Base | Representation |
---|---|
bin | 11111110000100001… |
… | …00101101101000111 |
3 | 1122000020120202021212 |
4 | 33320100211231013 |
5 | 234404300001244 |
6 | 11455504402035 |
7 | 1142341416251 |
oct | 177020455507 |
9 | 48006522255 |
10 | 17050000199 |
11 | 725a30a561 |
12 | 337a01631b |
13 | 17b947b91b |
14 | b7a5b6cd1 |
15 | 69bca1d9e |
hex | 3f8425b47 |
17050000199 has 2 divisors, whose sum is σ = 17050000200. Its totient is φ = 17050000198.
The previous prime is 17050000171. The next prime is 17050000223. The reversal of 17050000199 is 99100005071.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-17050000199 is a prime.
It is a super-3 number, since 3×170500001993 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17050000399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8525000099 + 8525000100.
It is an arithmetic number, because the mean of its divisors is an integer number (8525000100).
Almost surely, 217050000199 is an apocalyptic number.
17050000199 is a deficient number, since it is larger than the sum of its proper divisors (1).
17050000199 is an equidigital number, since it uses as much as digits as its factorization.
17050000199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2835, while the sum is 32.
The spelling of 17050000199 in words is "seventeen billion, fifty million, one hundred ninety-nine", and thus it is an aban number.
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