Base | Representation |
---|---|
bin | 11111110101110001… |
… | …00000000001011001 |
3 | 1122010022102001010221 |
4 | 33322320200001121 |
5 | 240002032021423 |
6 | 11504120040041 |
7 | 1143414514405 |
oct | 177270400131 |
9 | 48108361127 |
10 | 17094017113 |
11 | 7282144078 |
12 | 3390903021 |
13 | 17c5620934 |
14 | b82394105 |
15 | 6a0a98e5d |
hex | 3fae20059 |
17094017113 has 2 divisors, whose sum is σ = 17094017114. Its totient is φ = 17094017112.
The previous prime is 17094017069. The next prime is 17094017119. The reversal of 17094017113 is 31171049071.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16627586704 + 466430409 = 128948^2 + 21597^2 .
It is an emirp because it is prime and its reverse (31171049071) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17094017113 - 29 = 17094016601 is a prime.
It is not a weakly prime, because it can be changed into another prime (17094017119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8547008556 + 8547008557.
It is an arithmetic number, because the mean of its divisors is an integer number (8547008557).
Almost surely, 217094017113 is an apocalyptic number.
It is an amenable number.
17094017113 is a deficient number, since it is larger than the sum of its proper divisors (1).
17094017113 is an equidigital number, since it uses as much as digits as its factorization.
17094017113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5292, while the sum is 34.
The spelling of 17094017113 in words is "seventeen billion, ninety-four million, seventeen thousand, one hundred thirteen".
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