Base | Representation |
---|---|
bin | 11111110111000101… |
… | …11100000100000001 |
3 | 1122011002100020122102 |
4 | 33323202330010001 |
5 | 240012404021032 |
6 | 11505154320145 |
7 | 1143611210465 |
oct | 177342740401 |
9 | 48132306572 |
10 | 17105142017 |
11 | 7288452407 |
12 | 3394589055 |
13 | 17c7a17512 |
14 | b83a4c4a5 |
15 | 6a1a45362 |
hex | 3fb8bc101 |
17105142017 has 2 divisors, whose sum is σ = 17105142018. Its totient is φ = 17105142016.
The previous prime is 17105141897. The next prime is 17105142073. The reversal of 17105142017 is 71024150171.
17105142017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15485562481 + 1619579536 = 124441^2 + 40244^2 .
It is a cyclic number.
It is not a de Polignac number, because 17105142017 - 210 = 17105140993 is a prime.
It is not a weakly prime, because it can be changed into another prime (17105142097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8552571008 + 8552571009.
It is an arithmetic number, because the mean of its divisors is an integer number (8552571009).
Almost surely, 217105142017 is an apocalyptic number.
It is an amenable number.
17105142017 is a deficient number, since it is larger than the sum of its proper divisors (1).
17105142017 is an equidigital number, since it uses as much as digits as its factorization.
17105142017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1960, while the sum is 29.
Adding to 17105142017 its reverse (71024150171), we get a palindrome (88129292188).
The spelling of 17105142017 in words is "seventeen billion, one hundred five million, one hundred forty-two thousand, seventeen".
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