Base | Representation |
---|---|
bin | 11111111000111011… |
… | …00111101101001011 |
3 | 1122012011021210022101 |
4 | 33330131213231023 |
5 | 240030323301011 |
6 | 11510504134231 |
7 | 1144156030303 |
oct | 177435475513 |
9 | 48164253271 |
10 | 17120525131 |
11 | 72960a9a26 |
12 | 3399767377 |
13 | 17cac72358 |
14 | b85ad4603 |
15 | 6a30832c1 |
hex | 3fc767b4b |
17120525131 has 2 divisors, whose sum is σ = 17120525132. Its totient is φ = 17120525130.
The previous prime is 17120525119. The next prime is 17120525243. The reversal of 17120525131 is 13152502171.
It is a weak prime.
It is an emirp because it is prime and its reverse (13152502171) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17120525131 - 25 = 17120525099 is a prime.
It is a super-2 number, since 2×171205251312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 17120525131.
It is not a weakly prime, because it can be changed into another prime (17120525101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8560262565 + 8560262566.
It is an arithmetic number, because the mean of its divisors is an integer number (8560262566).
Almost surely, 217120525131 is an apocalyptic number.
17120525131 is a deficient number, since it is larger than the sum of its proper divisors (1).
17120525131 is an equidigital number, since it uses as much as digits as its factorization.
17120525131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2100, while the sum is 28.
The spelling of 17120525131 in words is "seventeen billion, one hundred twenty million, five hundred twenty-five thousand, one hundred thirty-one".
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