Base | Representation |
---|---|
bin | 1001111110000101001… |
… | …1001100010001000001 |
3 | 121101010001100220020121 |
4 | 2133201103030101001 |
5 | 10301242102112441 |
6 | 210404150340241 |
7 | 15242365553053 |
oct | 2374123142101 |
9 | 541101326217 |
10 | 171283629121 |
11 | 66706163790 |
12 | 2924265a681 |
13 | 131c8b7c747 |
14 | 840c3358d3 |
15 | 46c73a4dd1 |
hex | 27e14cc441 |
171283629121 has 4 divisors (see below), whose sum is σ = 186854868144. Its totient is φ = 155712390100.
The previous prime is 171283629103. The next prime is 171283629197. The reversal of 171283629121 is 121926382171.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 171283629121 - 215 = 171283596353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (171283629721) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7785619495 + ... + 7785619516.
It is an arithmetic number, because the mean of its divisors is an integer number (46713717036).
Almost surely, 2171283629121 is an apocalyptic number.
171283629121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
171283629121 is a deficient number, since it is larger than the sum of its proper divisors (15571239023).
171283629121 is a wasteful number, since it uses less digits than its factorization.
171283629121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15571239022.
The product of its digits is 72576, while the sum is 43.
The spelling of 171283629121 in words is "one hundred seventy-one billion, two hundred eighty-three million, six hundred twenty-nine thousand, one hundred twenty-one".
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