Base | Representation |
---|---|
bin | 11111111010000010… |
… | …11000111110101001 |
3 | 1122012210221011221120 |
4 | 33331001120332221 |
5 | 240040223330433 |
6 | 11511441125453 |
7 | 1144331523141 |
oct | 177501307651 |
9 | 48183834846 |
10 | 17129901993 |
11 | 72a04239a6 |
12 | 33a0929889 |
13 | 17ccba63a9 |
14 | b87055921 |
15 | 6a3cd67b3 |
hex | 3fd058fa9 |
17129901993 has 8 divisors (see below), whose sum is σ = 23180763168. Its totient is φ = 11249487744.
The previous prime is 17129901983. The next prime is 17129902007. The reversal of 17129901993 is 39910992171.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 17129901993 - 214 = 17129885609 is a prime.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is not an unprimeable number, because it can be changed into a prime (17129901983) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42611496 + ... + 42611897.
It is an arithmetic number, because the mean of its divisors is an integer number (2897595396).
Almost surely, 217129901993 is an apocalyptic number.
It is an amenable number.
17129901993 is a deficient number, since it is larger than the sum of its proper divisors (6050861175).
17129901993 is an equidigital number, since it uses as much as digits as its factorization.
17129901993 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85223463.
The product of its (nonzero) digits is 275562, while the sum is 51.
The spelling of 17129901993 in words is "seventeen billion, one hundred twenty-nine million, nine hundred one thousand, nine hundred ninety-three".
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