Base | Representation |
---|---|
bin | 11111111010000011… |
… | …00010100101100111 |
3 | 1122012211000011221021 |
4 | 33331001202211213 |
5 | 240040231110401 |
6 | 11511442032011 |
7 | 1144332045655 |
oct | 177501424547 |
9 | 48184004837 |
10 | 17129941351 |
11 | 72a0450526 |
12 | 33a0948607 |
13 | 17ccbbb293 |
14 | b87065dd5 |
15 | 6a3ce32a1 |
hex | 3fd062967 |
17129941351 has 8 divisors (see below), whose sum is σ = 17426223360. Its totient is φ = 16833857592.
The previous prime is 17129941337. The next prime is 17129941417. The reversal of 17129941351 is 15314992171.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 17129941351 - 215 = 17129908583 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 17129941298 and 17129941307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (17129941051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130336 + ... + 226378.
It is an arithmetic number, because the mean of its divisors is an integer number (2178277920).
Almost surely, 217129941351 is an apocalyptic number.
17129941351 is a deficient number, since it is larger than the sum of its proper divisors (296282009).
17129941351 is an equidigital number, since it uses as much as digits as its factorization.
17129941351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99125.
The product of its digits is 68040, while the sum is 43.
The spelling of 17129941351 in words is "seventeen billion, one hundred twenty-nine million, nine hundred forty-one thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •