1713070440031 has 4 divisors (see below), whose sum is σ = 1715669940600. Its totient is φ = 1710470939464.

The previous prime is 1713070440019. The next prime is 1713070440043. The reversal of 1713070440031 is 1300440703171.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1713070440019) and next prime (1713070440043).

It is a cyclic number.

It is not a de Polignac number, because 1713070440031 - 2⁵ = 1713070439999 is a prime.

It is a super-2 number, since 2×1713070440031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1713070439975 and 1713070440002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1713070440931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1299749296 + ... + 1299750613.

It is an arithmetic number, because the mean of its divisors is an integer number (428917485150).

Almost surely, 2^{1713070440031} is an apocalyptic number.

1713070440031 is a deficient number, since it is larger than the sum of its proper divisors (2599500569).

1713070440031 is an equidigital number, since it uses as much as digits as its factorization.

1713070440031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2599500568.

The product of its (nonzero) digits is 7056, while the sum is 31.

The spelling of 1713070440031 in words is "one trillion, seven hundred thirteen billion, seventy million, four hundred forty thousand, thirty-one".