Base | Representation |
---|---|
bin | 11111111010001100… |
… | …00000011111010111 |
3 | 1122012220012200022201 |
4 | 33331012000133113 |
5 | 240041031044112 |
6 | 11511523105331 |
7 | 1144345024063 |
oct | 177506003727 |
9 | 48186180281 |
10 | 17131112407 |
11 | 72a1080342 |
12 | 33a1212247 |
13 | 180020b306 |
14 | b8728caa3 |
15 | 6a3e75257 |
hex | 3fd1807d7 |
17131112407 has 4 divisors (see below), whose sum is σ = 17254357960. Its totient is φ = 17007866856.
The previous prime is 17131112393. The next prime is 17131112413. The reversal of 17131112407 is 70421113171.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70421113171 = 641 ⋅109861331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-17131112407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (17131112417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61622568 + ... + 61622845.
It is an arithmetic number, because the mean of its divisors is an integer number (4313589490).
Almost surely, 217131112407 is an apocalyptic number.
17131112407 is a deficient number, since it is larger than the sum of its proper divisors (123245553).
17131112407 is a wasteful number, since it uses less digits than its factorization.
17131112407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123245552.
The product of its (nonzero) digits is 1176, while the sum is 28.
Adding to 17131112407 its reverse (70421113171), we get a palindrome (87552225578).
The spelling of 17131112407 in words is "seventeen billion, one hundred thirty-one million, one hundred twelve thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •