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1714362430621 = 3155302013891
BaseRepresentation
bin11000111100100111111…
…101101011010010011101
320001220001212100220010211
4120330213331223102131
5211042003240234441
63351322304332421
7234600333140101
oct30744775532235
96056055326124
101714362430621
11601069998265
12238308614111
13c5882160829
145cd93009901
152e8db693a81
hex18f27f6b49d

1714362430621 has 4 divisors (see below), whose sum is σ = 1769664444544. Its totient is φ = 1659060416700.

The previous prime is 1714362430597. The next prime is 1714362430631. The reversal of 1714362430621 is 1260342634171.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1714362430621 - 211 = 1714362428573 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1714362430631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27651006915 + ... + 27651006976.

It is an arithmetic number, because the mean of its divisors is an integer number (442416111136).

Almost surely, 21714362430621 is an apocalyptic number.

It is an amenable number.

1714362430621 is a deficient number, since it is larger than the sum of its proper divisors (55302013923).

1714362430621 is an equidigital number, since it uses as much as digits as its factorization.

1714362430621 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55302013922.

The product of its (nonzero) digits is 145152, while the sum is 40.

The spelling of 1714362430621 in words is "one trillion, seven hundred fourteen billion, three hundred sixty-two million, four hundred thirty thousand, six hundred twenty-one".

Divisors: 1 31 55302013891 1714362430621