Base | Representation |
---|---|
bin | 11111111100001111… |
… | …00111011000110101 |
3 | 1122021002120110111002 |
4 | 33332013213120311 |
5 | 240104431423333 |
6 | 11513335453045 |
7 | 1144644145034 |
oct | 177607473065 |
9 | 48232513432 |
10 | 17148311093 |
11 | 72aa857a31 |
12 | 33a6b27185 |
13 | 1803950654 |
14 | b8968871b |
15 | 6a57210e8 |
hex | 3fe1e7635 |
17148311093 has 2 divisors, whose sum is σ = 17148311094. Its totient is φ = 17148311092.
The previous prime is 17148311069. The next prime is 17148311143. The reversal of 17148311093 is 39011384171.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9478580164 + 7669730929 = 97358^2 + 87577^2 .
It is an emirp because it is prime and its reverse (39011384171) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17148311093 - 26 = 17148311029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17148311293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8574155546 + 8574155547.
It is an arithmetic number, because the mean of its divisors is an integer number (8574155547).
Almost surely, 217148311093 is an apocalyptic number.
It is an amenable number.
17148311093 is a deficient number, since it is larger than the sum of its proper divisors (1).
17148311093 is an equidigital number, since it uses as much as digits as its factorization.
17148311093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 38.
The spelling of 17148311093 in words is "seventeen billion, one hundred forty-eight million, three hundred eleven thousand, ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •