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171500000047 is a prime number
BaseRepresentation
bin1001111110111000110…
…0100101001100101111
3121101200010111200100121
42133232030211030233
510302213000000142
6210441440105411
715250633643065
oct2375614451457
9541603450317
10171500000047
1166807308432
12292a3005267
131323194938c
14842cd7a035
1546db394c67
hex27ee32532f

171500000047 has 2 divisors, whose sum is σ = 171500000048. Its totient is φ = 171500000046.

The previous prime is 171499999967. The next prime is 171500000051. The reversal of 171500000047 is 740000005171.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 171500000047 - 219 = 171499475759 is a prime.

It is a super-2 number, since 2×1715000000472 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 171499999967 and 171500000030.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171500010047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85750000023 + 85750000024.

It is an arithmetic number, because the mean of its divisors is an integer number (85750000024).

Almost surely, 2171500000047 is an apocalyptic number.

171500000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

171500000047 is an equidigital number, since it uses as much as digits as its factorization.

171500000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 980, while the sum is 25.

The spelling of 171500000047 in words is "one hundred seventy-one billion, five hundred million, forty-seven", and thus it is an aban number.