Base | Representation |
---|---|
bin | 100111010001010110010111… |
… | …101111001101100110010011 |
3 | 211122112111100120120002202202 |
4 | 213101112113233031212103 |
5 | 140114240000244011011 |
6 | 1411200355402233415 |
7 | 51244216054441361 |
oct | 4721262757154623 |
9 | 748474316502682 |
10 | 172716065610131 |
11 | 5003a52137a41a |
12 | 17455644ab586b |
13 | 754b094099814 |
14 | 3091705d9c631 |
15 | 14e7b1b9a123b |
hex | 9d1597bcd993 |
172716065610131 has 2 divisors, whose sum is σ = 172716065610132. Its totient is φ = 172716065610130.
The previous prime is 172716065610071. The next prime is 172716065610133. The reversal of 172716065610131 is 131016560617271.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 172716065610131 - 222 = 172716061415827 is a prime.
It is a super-2 number, since 2×1727160656101312 (a number of 29 digits) contains 22 as substring.
Together with 172716065610133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (172716065610133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86358032805065 + 86358032805066.
It is an arithmetic number, because the mean of its divisors is an integer number (86358032805066).
Almost surely, 2172716065610131 is an apocalyptic number.
172716065610131 is a deficient number, since it is larger than the sum of its proper divisors (1).
172716065610131 is an equidigital number, since it uses as much as digits as its factorization.
172716065610131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 317520, while the sum is 47.
The spelling of 172716065610131 in words is "one hundred seventy-two trillion, seven hundred sixteen billion, sixty-five million, six hundred ten thousand, one hundred thirty-one".
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