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173144253748001 is a prime number
BaseRepresentation
bin100111010111100101001001…
…101111010101001100100001
3211201001102120202002020112212
4213113211021233111030201
5140143243412424414001
61412125212212131505
751320155005530354
oct4727451157251441
9751042522066485
10173144253748001
115019507a419a28
1217504624306b95
13757c5825b8883
1430a8325ac629b
151503d2cdc57bb
hex9d7949bd5321

173144253748001 has 2 divisors, whose sum is σ = 173144253748002. Its totient is φ = 173144253748000.

The previous prime is 173144253747953. The next prime is 173144253748003. The reversal of 173144253748001 is 100847352441371.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 149137242654976 + 24007011093025 = 12212176^2 + 4899695^2 .

It is a cyclic number.

It is not a de Polignac number, because 173144253748001 - 218 = 173144253485857 is a prime.

It is a super-2 number, since 2×1731442537480012 (a number of 29 digits) contains 22 as substring.

Together with 173144253748003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (173144253748003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86572126874000 + 86572126874001.

It is an arithmetic number, because the mean of its divisors is an integer number (86572126874001).

Almost surely, 2173144253748001 is an apocalyptic number.

It is an amenable number.

173144253748001 is a deficient number, since it is larger than the sum of its proper divisors (1).

173144253748001 is an equidigital number, since it uses as much as digits as its factorization.

173144253748001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2257920, while the sum is 50.

The spelling of 173144253748001 in words is "one hundred seventy-three trillion, one hundred forty-four billion, two hundred fifty-three million, seven hundred forty-eight thousand, one".