Base | Representation |
---|---|
bin | 110011101011011… |
… | …0011001100100001 |
3 | 11110211212212010112 |
4 | 1213112303030201 |
5 | 12022402430423 |
6 | 444022141105 |
7 | 60654004244 |
oct | 14726631441 |
9 | 4424785115 |
10 | 1734030113 |
11 | 80a8a6542 |
12 | 404881795 |
13 | 218332a2a |
14 | 12642325b |
15 | a2376a78 |
hex | 675b3321 |
1734030113 has 2 divisors, whose sum is σ = 1734030114. Its totient is φ = 1734030112.
The previous prime is 1734030091. The next prime is 1734030131. The reversal of 1734030113 is 3110304371.
Together with next prime (1734030131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1219965184 + 514064929 = 34928^2 + 22673^2 .
It is an emirp because it is prime and its reverse (3110304371) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1734030113 - 212 = 1734026017 is a prime.
It is not a weakly prime, because it can be changed into another prime (1734030163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 867015056 + 867015057.
It is an arithmetic number, because the mean of its divisors is an integer number (867015057).
Almost surely, 21734030113 is an apocalyptic number.
It is an amenable number.
1734030113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1734030113 is an equidigital number, since it uses as much as digits as its factorization.
1734030113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 23.
The square root of 1734030113 is about 41641.6872016493. The cubic root of 1734030113 is about 1201.3942389448.
Adding to 1734030113 its reverse (3110304371), we get a palindrome (4844334484).
The spelling of 1734030113 in words is "one billion, seven hundred thirty-four million, thirty thousand, one hundred thirteen".
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