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17385766403113 is a prime number
BaseRepresentation
bin1111110011111111000001…
…1011100011110000101001
32021120001200221201221221101
43330333300123203300221
54234322022144344423
6100550524423241401
73443036333053513
oct374776033436051
967501627657841
1017385766403113
1155a3297985749
121b49589ba9261
13991617294ab4
14441693004bb3
1520239c6637ad
hexfcff06e3c29

17385766403113 has 2 divisors, whose sum is σ = 17385766403114. Its totient is φ = 17385766403112.

The previous prime is 17385766403111. The next prime is 17385766403149. The reversal of 17385766403113 is 31130466758371.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17356155909184 + 29610493929 = 4166072^2 + 172077^2 .

It is a cyclic number.

It is not a de Polignac number, because 17385766403113 - 21 = 17385766403111 is a prime.

It is a super-2 number, since 2×173857664031132 (a number of 27 digits) contains 22 as substring.

Together with 17385766403111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (17385766403111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8692883201556 + 8692883201557.

It is an arithmetic number, because the mean of its divisors is an integer number (8692883201557).

Almost surely, 217385766403113 is an apocalyptic number.

It is an amenable number.

17385766403113 is a deficient number, since it is larger than the sum of its proper divisors (1).

17385766403113 is an equidigital number, since it uses as much as digits as its factorization.

17385766403113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7620480, while the sum is 55.

The spelling of 17385766403113 in words is "seventeen trillion, three hundred eighty-five billion, seven hundred sixty-six million, four hundred three thousand, one hundred thirteen".