Search a number
-
+
17412351340817 is a prime number
BaseRepresentation
bin1111110101100010000100…
…0001000011000100010001
32021122121022200222201112202
43331120201001003010101
54240240443420401232
6101011042422532545
73445000204232516
oct375304101030421
967577280881482
1017412351340817
11560359a435944
121b52769297155
13993c92c8c274
14442a95a8130d
15202e0655c162
hexfd621043111

17412351340817 has 2 divisors, whose sum is σ = 17412351340818. Its totient is φ = 17412351340816.

The previous prime is 17412351340793. The next prime is 17412351340871. The reversal of 17412351340817 is 71804315321471.

Together with next prime (17412351340871) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15367897476481 + 2044453864336 = 3920191^2 + 1429844^2 .

It is a cyclic number.

It is not a de Polignac number, because 17412351340817 - 216 = 17412351275281 is a prime.

It is not a weakly prime, because it can be changed into another prime (17412351340897) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8706175670408 + 8706175670409.

It is an arithmetic number, because the mean of its divisors is an integer number (8706175670409).

Almost surely, 217412351340817 is an apocalyptic number.

It is an amenable number.

17412351340817 is a deficient number, since it is larger than the sum of its proper divisors (1).

17412351340817 is an equidigital number, since it uses as much as digits as its factorization.

17412351340817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 564480, while the sum is 47.

The spelling of 17412351340817 in words is "seventeen trillion, four hundred twelve billion, three hundred fifty-one million, three hundred forty thousand, eight hundred seventeen".