1743113563121 has 4 divisors (see below), whose sum is σ = 1992129786432. Its totient is φ = 1494097339812.

The previous prime is 1743113563069. The next prime is 1743113563157. The reversal of 1743113563121 is 1213653113471.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1743113563121 - 2¹⁰ = 1743113562097 is a prime.

It is a super-3 number, since 3×1743113563121³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1743113563621) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124508111645 + ... + 124508111658.

It is an arithmetic number, because the mean of its divisors is an integer number (498032446608).

Almost surely, 2^{1743113563121} is an apocalyptic number.

It is an amenable number.

1743113563121 is a deficient number, since it is larger than the sum of its proper divisors (249016223311).

1743113563121 is an equidigital number, since it uses as much as digits as its factorization.

1743113563121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 249016223310.

The product of its digits is 45360, while the sum is 38.

Adding to 1743113563121 its reverse (1213653113471), we get a palindrome (2956766676592).

The spelling of 1743113563121 in words is "one trillion, seven hundred forty-three billion, one hundred thirteen million, five hundred sixty-three thousand, one hundred twenty-one".