Base | Representation |
---|---|
bin | 10000010010101010… |
… | …101101001000110001 |
3 | 1200011010021012211221 |
4 | 100102222231020301 |
5 | 241311210212001 |
6 | 12011452505041 |
7 | 1156331335303 |
oct | 202252551061 |
9 | 50133235757 |
10 | 17493054001 |
11 | 7467411425 |
12 | 348247b181 |
13 | 185a1b5a37 |
14 | bbd387973 |
15 | 6c5b1c1a1 |
hex | 412aad231 |
17493054001 has 2 divisors, whose sum is σ = 17493054002. Its totient is φ = 17493054000.
The previous prime is 17493053999. The next prime is 17493054017. The reversal of 17493054001 is 10045039471.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17016941601 + 476112400 = 130449^2 + 21820^2 .
It is an emirp because it is prime and its reverse (10045039471) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17493054001 - 21 = 17493053999 is a prime.
Together with 17493053999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (17493054071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8746527000 + 8746527001.
It is an arithmetic number, because the mean of its divisors is an integer number (8746527001).
Almost surely, 217493054001 is an apocalyptic number.
It is an amenable number.
17493054001 is a deficient number, since it is larger than the sum of its proper divisors (1).
17493054001 is an equidigital number, since it uses as much as digits as its factorization.
17493054001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 17493054001 in words is "seventeen billion, four hundred ninety-three million, fifty-four thousand, one".
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