Base | Representation |
---|---|
bin | 10000110000110101… |
… | …101101001100101111 |
3 | 1201110101202212010212 |
4 | 100300311231030233 |
5 | 243330302114234 |
6 | 12134014253035 |
7 | 1205016065054 |
oct | 206065551457 |
9 | 51411685125 |
10 | 17999254319 |
11 | 76a71231a2 |
12 | 35a3ab717b |
13 | 190b02c057 |
14 | c2a6b502b |
15 | 7052ac5ce |
hex | 430d6d32f |
17999254319 has 2 divisors, whose sum is σ = 17999254320. Its totient is φ = 17999254318.
The previous prime is 17999254309. The next prime is 17999254333. The reversal of 17999254319 is 91345299971.
It is a weak prime.
It is an emirp because it is prime and its reverse (91345299971) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17999254319 - 24 = 17999254303 is a prime.
It is a super-2 number, since 2×179992543192 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (17999254309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8999627159 + 8999627160.
It is an arithmetic number, because the mean of its divisors is an integer number (8999627160).
Almost surely, 217999254319 is an apocalyptic number.
17999254319 is a deficient number, since it is larger than the sum of its proper divisors (1).
17999254319 is an equidigital number, since it uses as much as digits as its factorization.
17999254319 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5511240, while the sum is 59.
The spelling of 17999254319 in words is "seventeen billion, nine hundred ninety-nine million, two hundred fifty-four thousand, three hundred nineteen".
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