Search a number
-
+
18059693 is a prime number
BaseRepresentation
bin100010011100…
…1000110101101
31020222112020112
41010321012231
514110402233
61443025405
7306335111
oct104710655
936875215
1018059693
11a215573
12606b265
133984212
142581741
1518bb048
hex11391ad

18059693 has 2 divisors, whose sum is σ = 18059694. Its totient is φ = 18059692.

The previous prime is 18059687. The next prime is 18059707. The reversal of 18059693 is 39695081.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18003049 + 56644 = 4243^2 + 238^2 .

It is an emirp because it is prime and its reverse (39695081) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 18059693 - 24 = 18059677 is a prime.

It is a super-2 number, since 2×180596932 = 652305022508498, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 18059693.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (18059683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9029846 + 9029847.

It is an arithmetic number, because the mean of its divisors is an integer number (9029847).

Almost surely, 218059693 is an apocalyptic number.

It is an amenable number.

18059693 is a deficient number, since it is larger than the sum of its proper divisors (1).

18059693 is an equidigital number, since it uses as much as digits as its factorization.

18059693 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58320, while the sum is 41.

The square root of 18059693 is about 4249.6697518748. The cubic root of 18059693 is about 262.3635233120.

The spelling of 18059693 in words is "eighteen million, fifty-nine thousand, six hundred ninety-three".