Base | Representation |
---|---|
bin | 1010100011000100010… |
… | …1010010001010101101 |
3 | 122022201222112020012121 |
4 | 2220301011102022231 |
5 | 10432110244021044 |
6 | 215125300032541 |
7 | 16043414252131 |
oct | 2506105221255 |
9 | 568658466177 |
10 | 181212095149 |
11 | 6a94055a208 |
12 | 2b153692751 |
13 | 1411bab2107 |
14 | 8ab0b973c1 |
15 | 4aa8d32984 |
hex | 2a311522ad |
181212095149 has 4 divisors (see below), whose sum is σ = 181225042720. Its totient is φ = 181199147580.
The previous prime is 181212095143. The next prime is 181212095203. The reversal of 181212095149 is 941590212181.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 181212095149 - 27 = 181212095021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (181212095143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6452769 + ... + 6480790.
It is an arithmetic number, because the mean of its divisors is an integer number (45306260680).
Almost surely, 2181212095149 is an apocalyptic number.
It is an amenable number.
181212095149 is a deficient number, since it is larger than the sum of its proper divisors (12947571).
181212095149 is a wasteful number, since it uses less digits than its factorization.
181212095149 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12947570.
The product of its (nonzero) digits is 51840, while the sum is 43.
The spelling of 181212095149 in words is "one hundred eighty-one billion, two hundred twelve million, ninety-five thousand, one hundred forty-nine".
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