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1825652103497 is a prime number
BaseRepresentation
bin11010100100010001010…
…110000101100101001001
320110112022211112001002222
4122210101112011211021
5214402413414302442
63514405404303425
7245620234556555
oct32442126054511
96415284461088
101825652103497
11644289021722
122559a7241b75
131032098bac81
146450d5c2865
1532751adb8d2
hex1a911585949

1825652103497 has 2 divisors, whose sum is σ = 1825652103498. Its totient is φ = 1825652103496.

The previous prime is 1825652103481. The next prime is 1825652103511. The reversal of 1825652103497 is 7943012565281.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1496668411456 + 328983692041 = 1223384^2 + 573571^2 .

It is an emirp because it is prime and its reverse (7943012565281) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1825652103497 - 24 = 1825652103481 is a prime.

It is not a weakly prime, because it can be changed into another prime (1825652103467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 912826051748 + 912826051749.

It is an arithmetic number, because the mean of its divisors is an integer number (912826051749).

It is a 1-persistent number, because it is pandigital, but 2⋅1825652103497 = 3651304206994 is not.

Almost surely, 21825652103497 is an apocalyptic number.

It is an amenable number.

1825652103497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1825652103497 is an equidigital number, since it uses as much as digits as its factorization.

1825652103497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3628800, while the sum is 53.

The spelling of 1825652103497 in words is "one trillion, eight hundred twenty-five billion, six hundred fifty-two million, one hundred three thousand, four hundred ninety-seven".