Search a number
-
+
182813131561 is a prime number
BaseRepresentation
bin1010101001000010000…
…0110000001100101001
3122110212120011022021111
42222100200300030221
510443400130202221
6215552211510321
716131164656564
oct2522040601451
9573776138244
10182813131561
11705922795a5
122b51b8b83a1
13143156bb838
148bc367b4db
154b4e688be1
hex2a90830329

182813131561 has 2 divisors, whose sum is σ = 182813131562. Its totient is φ = 182813131560.

The previous prime is 182813131513. The next prime is 182813131577. The reversal of 182813131561 is 165131318281.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 171263545600 + 11549585961 = 413840^2 + 107469^2 .

It is a cyclic number.

It is not a de Polignac number, because 182813131561 - 27 = 182813131433 is a prime.

It is a super-2 number, since 2×1828131315612 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (182813131861) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 91406565780 + 91406565781.

It is an arithmetic number, because the mean of its divisors is an integer number (91406565781).

Almost surely, 2182813131561 is an apocalyptic number.

It is an amenable number.

182813131561 is a deficient number, since it is larger than the sum of its proper divisors (1).

182813131561 is an equidigital number, since it uses as much as digits as its factorization.

182813131561 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 40.

The spelling of 182813131561 in words is "one hundred eighty-two billion, eight hundred thirteen million, one hundred thirty-one thousand, five hundred sixty-one".