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183401483143 is a prime number
BaseRepresentation
bin1010101011001110010…
…1001000101110000111
3122112101120020122220211
42222303211020232013
511001101234430033
6220130430140251
716151600612404
oct2526345105607
9575346218824
10183401483143
11708643a087a
122b664951687
13143aa569478
148c3b8712ab
154b861552cd
hex2ab3948b87

183401483143 has 2 divisors, whose sum is σ = 183401483144. Its totient is φ = 183401483142.

The previous prime is 183401483137. The next prime is 183401483147. The reversal of 183401483143 is 341384104381.

183401483143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-183401483143 is a prime.

It is a super-2 number, since 2×1834014831432 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 183401483096 and 183401483105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (183401483147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 91700741571 + 91700741572.

It is an arithmetic number, because the mean of its divisors is an integer number (91700741572).

Almost surely, 2183401483143 is an apocalyptic number.

183401483143 is a deficient number, since it is larger than the sum of its proper divisors (1).

183401483143 is an equidigital number, since it uses as much as digits as its factorization.

183401483143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 110592, while the sum is 40.

The spelling of 183401483143 in words is "one hundred eighty-three billion, four hundred one million, four hundred eighty-three thousand, one hundred forty-three".