Base | Representation |
---|---|
bin | 11010101100010100111… |
… | …100111011000001010001 |
3 | 20111100122200212021000002 |
4 | 122230110330323001101 |
5 | 220023122423100342 |
6 | 3522400021335345 |
7 | 246344504263523 |
oct | 32542474730121 |
9 | 6440580767002 |
10 | 1834302550097 |
11 | 647a17a73246 |
12 | 257600267555 |
13 | 103c87b10424 |
14 | 64ad0405a13 |
15 | 32aab26bd32 |
hex | 1ab14f3b051 |
1834302550097 has 2 divisors, whose sum is σ = 1834302550098. Its totient is φ = 1834302550096.
The previous prime is 1834302550061. The next prime is 1834302550099. The reversal of 1834302550097 is 7900552034381.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1763414020096 + 70888530001 = 1327936^2 + 266249^2 .
It is a cyclic number.
It is not a de Polignac number, because 1834302550097 - 28 = 1834302549841 is a prime.
Together with 1834302550099, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1834302550099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 917151275048 + 917151275049.
It is an arithmetic number, because the mean of its divisors is an integer number (917151275049).
Almost surely, 21834302550097 is an apocalyptic number.
It is an amenable number.
1834302550097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1834302550097 is an equidigital number, since it uses as much as digits as its factorization.
1834302550097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 907200, while the sum is 47.
The spelling of 1834302550097 in words is "one trillion, eight hundred thirty-four billion, three hundred two million, five hundred fifty thousand, ninety-seven".
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