183940231 has 2 divisors, whose sum is σ = 183940232. Its totient is φ = 183940230.

The previous prime is 183940213. The next prime is 183940241. The reversal of 183940231 is 132049381.

Together with previous prime (183940213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (132049381) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 183940231 - 2⁵ = 183940199 is a prime.

It is a super-2 number, since 2×183940231² = 67668017160666722, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 183940193 and 183940202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (183940241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 91970115 + 91970116.

It is an arithmetic number, because the mean of its divisors is an integer number (91970116).

Almost surely, 2^183940231 is an apocalyptic number.

183940231 is a deficient number, since it is larger than the sum of its proper divisors (1).

183940231 is an equidigital number, since it uses as much as digits as its factorization.

183940231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The square root of 183940231 is about 13562.4566727419. The cubic root of 183940231 is about 568.7118041249.

The spelling of 183940231 in words is "one hundred eighty-three million, nine hundred forty thousand, two hundred thirty-one".