Base | Representation |
---|---|
bin | 10001001110010001… |
… | …001110100011011001 |
3 | 1202201210212010222112 |
4 | 101032101032203121 |
5 | 300333202224324 |
6 | 12255013202105 |
7 | 1223162655323 |
oct | 211621164331 |
9 | 52653763875 |
10 | 18493008089 |
11 | 792a903766 |
12 | 3701330335 |
13 | 198940804a |
14 | c760c2613 |
15 | 7337dec0e |
hex | 44e44e8d9 |
18493008089 has 2 divisors, whose sum is σ = 18493008090. Its totient is φ = 18493008088.
The previous prime is 18493008071. The next prime is 18493008091. The reversal of 18493008089 is 98080039481.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14855953225 + 3637054864 = 121885^2 + 60308^2 .
It is a cyclic number.
It is not a de Polignac number, because 18493008089 - 212 = 18493003993 is a prime.
Together with 18493008091, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (18493008019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9246504044 + 9246504045.
It is an arithmetic number, because the mean of its divisors is an integer number (9246504045).
Almost surely, 218493008089 is an apocalyptic number.
It is an amenable number.
18493008089 is a deficient number, since it is larger than the sum of its proper divisors (1).
18493008089 is an equidigital number, since it uses as much as digits as its factorization.
18493008089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 50.
The spelling of 18493008089 in words is "eighteen billion, four hundred ninety-three million, eight thousand, eighty-nine".
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