Base | Representation |
---|---|
bin | 10001001110100001… |
… | …110011110101101001 |
3 | 1202202010000222222102 |
4 | 101032201303311221 |
5 | 300340310330423 |
6 | 12255250303145 |
7 | 1223244632006 |
oct | 211641636551 |
9 | 52663028872 |
10 | 18497355113 |
11 | 7932302746 |
12 | 3702887ab5 |
13 | 198a29a853 |
14 | c768d48ad |
15 | 733d9cc28 |
hex | 44e873d69 |
18497355113 has 4 divisors (see below), whose sum is σ = 19301587968. Its totient is φ = 17693122260.
The previous prime is 18497355103. The next prime is 18497355119. The reversal of 18497355113 is 31155379481.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31155379481 = 119827 ⋅260003.
It is a cyclic number.
It is not a de Polignac number, because 18497355113 - 210 = 18497354089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (18497355119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402116393 + ... + 402116438.
It is an arithmetic number, because the mean of its divisors is an integer number (4825396992).
Almost surely, 218497355113 is an apocalyptic number.
It is an amenable number.
18497355113 is a deficient number, since it is larger than the sum of its proper divisors (804232855).
18497355113 is an equidigital number, since it uses as much as digits as its factorization.
18497355113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 804232854.
The product of its digits is 453600, while the sum is 47.
The spelling of 18497355113 in words is "eighteen billion, four hundred ninety-seven million, three hundred fifty-five thousand, one hundred thirteen".
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