Base | Representation |
---|---|
bin | 10001001110100100… |
… | …000101011001010101 |
3 | 1202202011011021211001 |
4 | 101032210011121111 |
5 | 300340433420232 |
6 | 12255311143301 |
7 | 1223252664136 |
oct | 211644053125 |
9 | 52664137731 |
10 | 18497951317 |
11 | 793267a67a |
12 | 3702b14b31 |
13 | 198a449031 |
14 | c76a0bc8d |
15 | 733e696e7 |
hex | 44e905655 |
18497951317 has 8 divisors (see below), whose sum is σ = 19176618240. Its totient is φ = 17824406880.
The previous prime is 18497951287. The next prime is 18497951321. The reversal of 18497951317 is 71315979481.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 18497951317 - 211 = 18497949269 is a prime.
It is a super-2 number, since 2×184979513172 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (18497951327) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1273267 + ... + 1287712.
It is an arithmetic number, because the mean of its divisors is an integer number (2397077280).
Almost surely, 218497951317 is an apocalyptic number.
It is an amenable number.
18497951317 is a deficient number, since it is larger than the sum of its proper divisors (678666923).
18497951317 is a wasteful number, since it uses less digits than its factorization.
18497951317 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2561243.
The product of its digits is 1905120, while the sum is 55.
The spelling of 18497951317 in words is "eighteen billion, four hundred ninety-seven million, nine hundred fifty-one thousand, three hundred seventeen".
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