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185290000433 is a prime number
BaseRepresentation
bin1010110010010000100…
…1010000100000110001
3122201021011211021121122
42230210021100200301
511013433220003213
6221042051432025
716246442005616
oct2544411204061
9581234737548
10185290000433
117164341386a
122bab12b5615
131461b8ac615
148d7a5ca50d
154c46d45d08
hex2b24250831

185290000433 has 2 divisors, whose sum is σ = 185290000434. Its totient is φ = 185290000432.

The previous prime is 185290000417. The next prime is 185290000457. The reversal of 185290000433 is 334000092581.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 182117269504 + 3172730929 = 426752^2 + 56327^2 .

It is a cyclic number.

It is not a de Polignac number, because 185290000433 - 24 = 185290000417 is a prime.

It is a super-2 number, since 2×1852900004332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 185290000393 and 185290000402.

It is not a weakly prime, because it can be changed into another prime (185290000033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 92645000216 + 92645000217.

It is an arithmetic number, because the mean of its divisors is an integer number (92645000217).

Almost surely, 2185290000433 is an apocalyptic number.

It is an amenable number.

185290000433 is a deficient number, since it is larger than the sum of its proper divisors (1).

185290000433 is an equidigital number, since it uses as much as digits as its factorization.

185290000433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 185290000433 in words is "one hundred eighty-five billion, two hundred ninety million, four hundred thirty-three", and thus it is an aban number.