Base | Representation |
---|---|
bin | 11011000101101000100… |
… | …011100011000000010011 |
3 | 20120221210101121010102222 |
4 | 123011220203203000103 |
5 | 220444300044104201 |
6 | 3543052205131255 |
7 | 251326041221330 |
oct | 33055043430023 |
9 | 6527711533388 |
10 | 1861474988051 |
11 | 6584a1114038 |
12 | 260924259b2b |
13 | 1066c8447b93 |
14 | 6614b0d3987 |
15 | 3364ba1491b |
hex | 1b1688e3013 |
1861474988051 has 4 divisors (see below), whose sum is σ = 2127399986352. Its totient is φ = 1595549989752.
The previous prime is 1861474988047. The next prime is 1861474988063. The reversal of 1861474988051 is 1508894741681.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1861474988051 - 22 = 1861474988047 is a prime.
It is a super-2 number, since 2×18614749880512 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1867474988051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132962499140 + ... + 132962499153.
It is an arithmetic number, because the mean of its divisors is an integer number (531849996588).
Almost surely, 21861474988051 is an apocalyptic number.
1861474988051 is a deficient number, since it is larger than the sum of its proper divisors (265924998301).
1861474988051 is an equidigital number, since it uses as much as digits as its factorization.
1861474988051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 265924998300.
The product of its (nonzero) digits is 15482880, while the sum is 62.
The spelling of 1861474988051 in words is "one trillion, eight hundred sixty-one billion, four hundred seventy-four million, nine hundred eighty-eight thousand, fifty-one".
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