Base | Representation |
---|---|
bin | 11011000111010110110… |
… | …010100000100100101101 |
3 | 20121010120021121012012110 |
4 | 123013112302200210231 |
5 | 221012042021412023 |
6 | 3543555512354233 |
7 | 251422626051522 |
oct | 33072662404455 |
9 | 6533507535173 |
10 | 1863324404013 |
11 | 65926005a686 |
12 | 26115b6a5979 |
13 | 10693164a557 |
14 | 66284991149 |
15 | 3370907ea93 |
hex | 1b1d6ca092d |
1863324404013 has 4 divisors (see below), whose sum is σ = 2484432538688. Its totient is φ = 1242216269340.
The previous prime is 1863324403903. The next prime is 1863324404017. The reversal of 1863324404013 is 3104044233681.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1863324404013 - 214 = 1863324387629 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1863324404017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310554067333 + ... + 310554067338.
It is an arithmetic number, because the mean of its divisors is an integer number (621108134672).
Almost surely, 21863324404013 is an apocalyptic number.
It is an amenable number.
1863324404013 is a deficient number, since it is larger than the sum of its proper divisors (621108134675).
1863324404013 is an equidigital number, since it uses as much as digits as its factorization.
1863324404013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 621108134674.
The product of its (nonzero) digits is 165888, while the sum is 39.
Adding to 1863324404013 its reverse (3104044233681), we get a palindrome (4967368637694).
The spelling of 1863324404013 in words is "one trillion, eight hundred sixty-three billion, three hundred twenty-four million, four hundred four thousand, thirteen".
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