Base | Representation |
---|---|
bin | 10001100001011010… |
… | …101100010100010001 |
3 | 1210120012100020211011 |
4 | 101201122230110101 |
5 | 302012422201101 |
6 | 12350530450521 |
7 | 1234143353323 |
oct | 214132542421 |
9 | 53505306734 |
10 | 18814256401 |
11 | 7a85180336 |
12 | 3790a33a41 |
13 | 1a0ab354c5 |
14 | ca6a27613 |
15 | 751ae9751 |
hex | 4616ac511 |
18814256401 has 2 divisors, whose sum is σ = 18814256402. Its totient is φ = 18814256400.
The previous prime is 18814256389. The next prime is 18814256441. The reversal of 18814256401 is 10465241881.
It is an a-pointer prime, because the next prime (18814256441) can be obtained adding 18814256401 to its sum of digits (40).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12414416400 + 6399840001 = 111420^2 + 79999^2 .
It is a cyclic number.
It is not a de Polignac number, because 18814256401 - 223 = 18805867793 is a prime.
It is not a weakly prime, because it can be changed into another prime (18814256441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9407128200 + 9407128201.
It is an arithmetic number, because the mean of its divisors is an integer number (9407128201).
Almost surely, 218814256401 is an apocalyptic number.
It is an amenable number.
18814256401 is a deficient number, since it is larger than the sum of its proper divisors (1).
18814256401 is an equidigital number, since it uses as much as digits as its factorization.
18814256401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61440, while the sum is 40.
The spelling of 18814256401 in words is "eighteen billion, eight hundred fourteen million, two hundred fifty-six thousand, four hundred one".
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