Base | Representation |
---|---|
bin | 10001110011000111… |
… | …010110001010010111 |
3 | 1211022220001021022011 |
4 | 101303013112022113 |
5 | 303114430043212 |
6 | 12440214445051 |
7 | 1244410206544 |
oct | 216307261227 |
9 | 54286037264 |
10 | 19111174807 |
11 | 811783a54a |
12 | 3854363787 |
13 | 1a574c477a |
14 | cd4237bcb |
15 | 76cbea4a7 |
hex | 4731d6297 |
19111174807 has 4 divisors (see below), whose sum is σ = 19111480696. Its totient is φ = 19110868920.
The previous prime is 19111174793. The next prime is 19111174813. The reversal of 19111174807 is 70847111191.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 19111174807 - 27 = 19111174679 is a prime.
It is a super-2 number, since 2×191111748072 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 19111174807.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19111172807) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21669 + ... + 196702.
It is an arithmetic number, because the mean of its divisors is an integer number (4777870174).
Almost surely, 219111174807 is an apocalyptic number.
19111174807 is a deficient number, since it is larger than the sum of its proper divisors (305889).
19111174807 is an equidigital number, since it uses as much as digits as its factorization.
19111174807 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 305888.
The product of its (nonzero) digits is 14112, while the sum is 40.
Adding to 19111174807 its reverse (70847111191), we get a palindrome (89958285998).
The spelling of 19111174807 in words is "nineteen billion, one hundred eleven million, one hundred seventy-four thousand, eight hundred seven".
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