Base | Representation |
---|---|
bin | 10001110011011101… |
… | …100011110011110001 |
3 | 1211100022000010001021 |
4 | 101303131203303301 |
5 | 303122422412443 |
6 | 12440543335441 |
7 | 1244510541451 |
oct | 216335436361 |
9 | 54308003037 |
10 | 19116997873 |
11 | 81200574a6 |
12 | 38562b1581 |
13 | 1a5878307c |
14 | cd4d11d61 |
15 | 76d49a9ed |
hex | 473763cf1 |
19116997873 has 2 divisors, whose sum is σ = 19116997874. Its totient is φ = 19116997872.
The previous prime is 19116997871. The next prime is 19116997927. The reversal of 19116997873 is 37879961191.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15847788544 + 3269209329 = 125888^2 + 57177^2 .
It is an emirp because it is prime and its reverse (37879961191) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19116997873 - 21 = 19116997871 is a prime.
Together with 19116997871, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (19116997871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9558498936 + 9558498937.
It is an arithmetic number, because the mean of its divisors is an integer number (9558498937).
Almost surely, 219116997873 is an apocalyptic number.
It is an amenable number.
19116997873 is a deficient number, since it is larger than the sum of its proper divisors (1).
19116997873 is an equidigital number, since it uses as much as digits as its factorization.
19116997873 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5143824, while the sum is 61.
The spelling of 19116997873 in words is "nineteen billion, one hundred sixteen million, nine hundred ninety-seven thousand, eight hundred seventy-three".
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