Base | Representation |
---|---|
bin | 1011001101000000110… |
… | …0011110000001010011 |
3 | 200101210200001210011112 |
4 | 2303100030132001103 |
5 | 11123140200200033 |
6 | 224230432003535 |
7 | 16622423451065 |
oct | 2632014360123 |
9 | 611720053145 |
10 | 192471490643 |
11 | 74699158743 |
12 | 313763905ab |
13 | 151c468b803 |
14 | 945c2ab735 |
15 | 501755ec48 |
hex | 2cd031e053 |
192471490643 has 4 divisors (see below), whose sum is σ = 192694517568. Its totient is φ = 192248463720.
The previous prime is 192471490639. The next prime is 192471490727. The reversal of 192471490643 is 346094174291.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 192471490643 - 22 = 192471490639 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 192471490591 and 192471490600.
It is not an unprimeable number, because it can be changed into a prime (192471490243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111512168 + ... + 111513893.
It is an arithmetic number, because the mean of its divisors is an integer number (48173629392).
Almost surely, 2192471490643 is an apocalyptic number.
192471490643 is a deficient number, since it is larger than the sum of its proper divisors (223026925).
192471490643 is an equidigital number, since it uses as much as digits as its factorization.
192471490643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223026924.
The product of its (nonzero) digits is 1306368, while the sum is 50.
The spelling of 192471490643 in words is "one hundred ninety-two billion, four hundred seventy-one million, four hundred ninety thousand, six hundred forty-three".
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