Base | Representation |
---|---|
bin | 11100000110101100100… |
… | …110101100101001011111 |
3 | 20211122010010200102112021 |
4 | 130012230212230221133 |
5 | 223120334023011112 |
6 | 4035124340121011 |
7 | 256351211223301 |
oct | 34065446545137 |
9 | 6748103612467 |
10 | 1931336141407 |
11 | 6850909a1612 |
12 | 272380696167 |
13 | 11017cb9a14a |
14 | 696974c5971 |
15 | 35389d4a907 |
hex | 1c1ac9aca5f |
1931336141407 has 2 divisors, whose sum is σ = 1931336141408. Its totient is φ = 1931336141406.
The previous prime is 1931336141393. The next prime is 1931336141417. The reversal of 1931336141407 is 7041416331391.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1931336141407 is a prime.
It is a super-2 number, since 2×19313361414072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1931336141417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 965668070703 + 965668070704.
It is an arithmetic number, because the mean of its divisors is an integer number (965668070704).
Almost surely, 21931336141407 is an apocalyptic number.
1931336141407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1931336141407 is an equidigital number, since it uses as much as digits as its factorization.
1931336141407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 163296, while the sum is 43.
The spelling of 1931336141407 in words is "one trillion, nine hundred thirty-one billion, three hundred thirty-six million, one hundred forty-one thousand, four hundred seven".
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