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19314050471 is a prime number
BaseRepresentation
bin10001111111001101…
…010000010110100111
31211212000210102101122
4101333031100112213
5304023344103341
612512303044155
71252422502022
oct217715202647
954760712348
1019314050471
118211306a91
1238b02a065b
131a8a547941
14d131681b9
1578092194b
hex47f3505a7

19314050471 has 2 divisors, whose sum is σ = 19314050472. Its totient is φ = 19314050470.

The previous prime is 19314050443. The next prime is 19314050477. The reversal of 19314050471 is 17405041391.

It is a strong prime.

It is an emirp because it is prime and its reverse (17405041391) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-19314050471 is a prime.

It is a super-3 number, since 3×193140504713 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19314050477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9657025235 + 9657025236.

It is an arithmetic number, because the mean of its divisors is an integer number (9657025236).

Almost surely, 219314050471 is an apocalyptic number.

19314050471 is a deficient number, since it is larger than the sum of its proper divisors (1).

19314050471 is an equidigital number, since it uses as much as digits as its factorization.

19314050471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 35.

The spelling of 19314050471 in words is "nineteen billion, three hundred fourteen million, fifty thousand, four hundred seventy-one".