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1933401202241 is a prime number
BaseRepresentation
bin11100001000100111101…
…100010001111001000001
320211211110001110101102212
4130020213230101321001
5223134101201432431
64040105305351505
7256453325030645
oct34104754217101
96754401411385
101933401202241
11685a50636363
12272858198595
1311041b973b32
1469811878c25
153545b2b072b
hex1c227b11e41

1933401202241 has 2 divisors, whose sum is σ = 1933401202242. Its totient is φ = 1933401202240.

The previous prime is 1933401202237. The next prime is 1933401202273. The reversal of 1933401202241 is 1422021043391.

It is an a-pointer prime, because the next prime (1933401202273) can be obtained adding 1933401202241 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1021118334016 + 912282868225 = 1010504^2 + 955135^2 .

It is a cyclic number.

It is not a de Polignac number, because 1933401202241 - 22 = 1933401202237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1933401202198 and 1933401202207.

It is not a weakly prime, because it can be changed into another prime (1933401222241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 966700601120 + 966700601121.

It is an arithmetic number, because the mean of its divisors is an integer number (966700601121).

Almost surely, 21933401202241 is an apocalyptic number.

It is an amenable number.

1933401202241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1933401202241 is an equidigital number, since it uses as much as digits as its factorization.

1933401202241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 1933401202241 in words is "one trillion, nine hundred thirty-three billion, four hundred one million, two hundred two thousand, two hundred forty-one".