Base | Representation |
---|---|
bin | 10010000001110011… |
… | …101100011011000001 |
3 | 1211222001220002200221 |
4 | 102001303230123001 |
5 | 304121031300340 |
6 | 12520502143041 |
7 | 1253462401522 |
oct | 220163543301 |
9 | 54861802627 |
10 | 19357681345 |
11 | 82339a7562 |
12 | 3902a21a81 |
13 | 1a965b3022 |
14 | d18c84849 |
15 | 78468e44a |
hex | 481cec6c1 |
19357681345 has 4 divisors (see below), whose sum is σ = 23229217620. Its totient is φ = 15486145072.
The previous prime is 19357681333. The next prime is 19357681373. The reversal of 19357681345 is 54318675391.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10431966769 + 8925714576 = 102137^2 + 94476^2 .
It is a cyclic number.
It is not a de Polignac number, because 19357681345 - 223 = 19349292737 is a prime.
It is a super-2 number, since 2×193576813452 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 19357681292 and 19357681301.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1935768130 + ... + 1935768139.
It is an arithmetic number, because the mean of its divisors is an integer number (5807304405).
Almost surely, 219357681345 is an apocalyptic number.
It is an amenable number.
19357681345 is a deficient number, since it is larger than the sum of its proper divisors (3871536275).
19357681345 is an equidigital number, since it uses as much as digits as its factorization.
19357681345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3871536274.
The product of its digits is 2721600, while the sum is 52.
The spelling of 19357681345 in words is "nineteen billion, three hundred fifty-seven million, six hundred eighty-one thousand, three hundred forty-five".
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