Base | Representation |
---|---|
bin | 10010001011011110… |
… | …100111100011100111 |
3 | 1212101101012010000201 |
4 | 102023132213203213 |
5 | 304434100203201 |
6 | 12544535451331 |
7 | 1260502440454 |
oct | 221336474347 |
9 | 55341163021 |
10 | 19519928551 |
11 | 8307544262 |
12 | 3949226b47 |
13 | 1ac10ac5a6 |
14 | d3263a82b |
15 | 793a3c801 |
hex | 48b7a78e7 |
19519928551 has 2 divisors, whose sum is σ = 19519928552. Its totient is φ = 19519928550.
The previous prime is 19519928543. The next prime is 19519928587. The reversal of 19519928551 is 15582991591.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 19519928551 - 23 = 19519928543 is a prime.
It is a super-2 number, since 2×195199285512 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 19519928492 and 19519928501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19519928501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9759964275 + 9759964276.
It is an arithmetic number, because the mean of its divisors is an integer number (9759964276).
Almost surely, 219519928551 is an apocalyptic number.
19519928551 is a deficient number, since it is larger than the sum of its proper divisors (1).
19519928551 is an equidigital number, since it uses as much as digits as its factorization.
19519928551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1458000, while the sum is 55.
The spelling of 19519928551 in words is "nineteen billion, five hundred nineteen million, nine hundred twenty-eight thousand, five hundred fifty-one".
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