Base | Representation |
---|---|
bin | 1000111010011011101111… |
… | …10110010000110110000001 |
3 | 2120101201212222012022001101 |
4 | 10131031313312100312001 |
5 | 10032111142300010441 |
6 | 105404031402534401 |
7 | 4062022642163542 |
oct | 435156766206601 |
9 | 76351788168041 |
10 | 19599946485121 |
11 | 6277321904172 |
12 | 2246726507401 |
13 | ac23618594b2 |
14 | 4ba8dcd284c9 |
15 | 23ec8d91b231 |
hex | 11d377d90d81 |
19599946485121 has 2 divisors, whose sum is σ = 19599946485122. Its totient is φ = 19599946485120.
The previous prime is 19599946485113. The next prime is 19599946485247. The reversal of 19599946485121 is 12158464999591.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18945683896896 + 654262588225 = 4352664^2 + 808865^2 .
It is a cyclic number.
It is not a de Polignac number, because 19599946485121 - 23 = 19599946485113 is a prime.
It is not a weakly prime, because it can be changed into another prime (19599946405121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9799973242560 + 9799973242561.
It is an arithmetic number, because the mean of its divisors is an integer number (9799973242561).
Almost surely, 219599946485121 is an apocalyptic number.
It is an amenable number.
19599946485121 is a deficient number, since it is larger than the sum of its proper divisors (1).
19599946485121 is an equidigital number, since it uses as much as digits as its factorization.
19599946485121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 251942400, while the sum is 73.
The spelling of 19599946485121 in words is "nineteen trillion, five hundred ninety-nine billion, nine hundred forty-six million, four hundred eighty-five thousand, one hundred twenty-one".
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