Base | Representation |
---|---|
bin | 10010010000110100… |
… | …011001011010001101 |
3 | 1212121121210000200020 |
4 | 102100310121122031 |
5 | 310130014230403 |
6 | 13001500052353 |
7 | 1262641126323 |
oct | 222064313215 |
9 | 55547700606 |
10 | 19609523853 |
11 | 8353079567 |
12 | 39732340b9 |
13 | 1b0681c26a |
14 | d404bdd13 |
15 | 79b839453 |
hex | 490d1968d |
19609523853 has 4 divisors (see below), whose sum is σ = 26146031808. Its totient is φ = 13073015900.
The previous prime is 19609523831. The next prime is 19609523873. The reversal of 19609523853 is 35832590691.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 19609523853 - 25 = 19609523821 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 19609523796 and 19609523805.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19609523803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3268253973 + ... + 3268253978.
It is an arithmetic number, because the mean of its divisors is an integer number (6536507952).
Almost surely, 219609523853 is an apocalyptic number.
It is an amenable number.
19609523853 is a deficient number, since it is larger than the sum of its proper divisors (6536507955).
19609523853 is an equidigital number, since it uses as much as digits as its factorization.
19609523853 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6536507954.
The product of its (nonzero) digits is 1749600, while the sum is 51.
The spelling of 19609523853 in words is "nineteen billion, six hundred nine million, five hundred twenty-three thousand, eight hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •